#include <stdio.h>
#include <stdlib.h>

/*
 * Note:
 *
 * All probabilities have denominators that are powers of 2, so there
 * is no need to use rational numbers to represent them precisely (up
 * to a point...)
 *
 */

#define MAX_M 50
#define MAX_T 40    /* should increase this to prevent brute force */
                    /* 40 should be safe even if we use float to store prob */
#define LOSE_TURN 2*MAX_M        /* guaranteed not one of the values */

/* 
 * pad the table to have one more row (for "negative" turns), and
 * one column for the start, two columns for end 
 */
float prob[MAX_T+2][MAX_M+3];

int m, t;
int board[MAX_M+3];

void read_case(void)
{
  char buffer[1024];
  int i;
  

  scanf("%d %d", &m, &t);
  for (i = 1; i <= m; i++) {
    scanf("%s", buffer);
    if (buffer[0] == 'L') {
      board[i] = LOSE_TURN;
    } else {
      board[i] = atoi(buffer);
    }
  }
  board[0] = board[m+1] = board[m+2] = 0;
}

void solve_case(void)
{
  int i, j, k, s;

  /* initialize probabilities for running out of turns */
  for (i = 0; i < m+3; i++) {
    prob[0][i] = prob[1][i] = 0.0;
  }

  /* initialize probabilities for being already at the end */
  for (i = 1; i <= t+1; i++) {
    prob[i][m+1] = prob[i][m+2] = 1.0;
  }

  /* now do dynamic programming */
  for (i = 2; i <= t+1; i++) {
    for (j = 0; j <= m; j++) {
      /* go one step */
      s = j+1;
      k = i-1;
      if (board[s] == LOSE_TURN) {
	k--;
      } else {
	s += board[s];
      }
      prob[i][j] = 0.5 * prob[k][s];

      /* go two steps */
      s = j+2;
      k = i-1;
      if (board[s] == LOSE_TURN) {
	k--;
      } else {
	s += board[s];
      }
      prob[i][j] += 0.5 * prob[k][s];
    }
  }

  /* print result */
  if (prob[t+1][0] < 0.5) {
    printf("Bet against. %.4f\n", prob[t+1][0]);
  } else if (prob[t+1][0] == 0.5) {
    printf("Push. %.4f\n", prob[t+1][0]);
  } else {
    printf("Bet for. %.4f\n", prob[t+1][0]);
  }
}

int main(void)
{
  int n;

  scanf("%d", &n);
  while (n-- > 0) {
    read_case();
    solve_case();
  }

  return 0;
}