/*
Author: Yiu Yu Ho

This is a simple geometry problem.
You need to know how to compute distance between 2 points, 
intersection point of 2 segments, and area of triangle.
*/

#include <iostream>
#include <cmath>
#include <cstdlib>
#include <algorithm>

using namespace std;

const double tol=1e-12;
const int L=64;

bool eq(double x,double y)
{
	return abs(x-y)<tol;
}

class Pair
{
public:
	double x,y;
	
	Pair() {}

	Pair(double xx, double yy) { x=xx; y=yy; }

	double dist(Pair p)
	{
		double dx, dy;
		dx=x-p.x; dy=y-p.y;

		return sqrt(dx*dx+dy*dy);
	}
};

class Triangle
{
public:
	Pair a, b, c;
	double area, outputArea, perimeter;

	Triangle() {}

	Triangle(Pair aa, Pair bb, Pair cc) 
	{ 
		a=aa; b=bb; c=cc; 

		double A,B,C,S;
		A=a.dist(b);
		B=b.dist(c);
		C=c.dist(a);
		S=(A+B+C)/2;

		area = sqrt(S*(S-A)*(S-B)*(S-C));
		perimeter = A+B+C;
		
		char buf[L];
		sprintf(buf,"%.3lf",area+tol);
		sscanf(buf,"%lf",&outputArea);

		//outputArea = area;
	}
};

bool operator<(Triangle A,Triangle B)
{
	if(!eq(A.outputArea,B.outputArea))
	{
		return A.outputArea > B.outputArea;
	}
	return A.perimeter > B.perimeter;
}

Pair inter(Pair a, Pair da, Pair b, Pair db)
{
	double det, at;
	det = (da.x)*(-db.y)-(-db.x)*(da.y);
	at = (-db.y)*(b.x-a.x)+(db.x)*(b.y-a.y);
	at = at/det;
	return Pair(a.x+at*da.x,a.y+at*da.y);
}

bool allZero(double v[8])
{
	for(int i=0;i<8;++i)
	if(!eq(v[i],0)) return false;

	return true;
}

void solve()
{
	double v[8];
	int i,j,k;
	Triangle T[4];
	Pair p;

	cout.precision(3);
	cout.setf(ios::fixed | ios::showpoint);

	for(i=0;i<8;++i) cin>>v[i];
	while(!allZero(v))
	{		
		p=inter(Pair(v[0],v[1]),Pair(v[4]-v[0],v[5]-v[1]),
			Pair(v[2],v[3]),Pair(v[6]-v[2],v[7]-v[3]));
		k=0;
		i=6;
		for(j=0;j<8;j+=2)
		{
			T[k]=Triangle(Pair(v[i],v[i+1]),Pair(v[j],v[j+1]),p);
			++k;
			i=j;
		}

		sort(T,T+4);
		for(i=0;i<4;++i)
		{
			if(i>0) cout<<' ';
			cout<<(T[i].outputArea+tol)<<' '<<(T[i].perimeter+tol);
		}
		cout<<endl;

		for(i=0;i<8;++i) cin>>v[i];
	}
}

int main()
{
	clock_t start = clock();
	solve();
	clock_t end = clock();
	cerr<<"Time = "<<(double)(end-start)/(CLOCKS_PER_SEC)<<" sec"<<endl;
	return 0;
}