Problem A: Practice

We assume that p, the probability that a given team will win a given contest, is related to n, the number of practice problems solved by the team prior to the contest. This relationship is modelled by the logistic formula

   log(p/(1-p)) = a + b n ,

Each observation consists of n and w. n is the number of practice problems solved by some team prior to a contest, and w is 1 if the team wins the contest, 0 if it does not.

Given a, b, and n the formula above may be used to compute p, the estimated probability that w = 1. The likelihood of a particular observation is p if w = 1 and 1-p if w = 0; The likelihood of a set of observations is the product of the likelihoods of the individual observations.

You are to compute the maximum likelihood estimate for a and b. That is, the values of a and b for which the likelihood of a given set of observations is maximized.

The input contains several test cases followed by a line contatining 0. Each test case begins with 1 < k ≤ 100, the number of observations that follow. Each observation consists of integers 0 ≤ n ≤ 100 and 0 ≤ w ≤ 1. The input will contain at least two distinct values of n and of w. For each test case, output a single line containing a and b, rounded to four digits to the right of the decimal.

Sample Input

20
0 0
0 0
0 0
0 0
1 0
1 0
1 0
1 1
2 0
2 0
2 1
2 1
3 0
3 1
3 1
3 1
4 1
4 1
4 1
4 1
0

Output for Sample Input

-3.1748 1.5874

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